Tom Adam
06/03/2019, 5:11 PM(5 downTo 3  step 3).forEach { println(it) }(5 downTo 3).filter { it % 2 == 0}
        .forEach { println(it) }(5 downTo 3  filter { it % 2 == 0})
        .forEach { println(it) }stepTom Adam
06/04/2019, 6:52 AMelizarov
06/04/2019, 10:09 AMhho
06/04/2019, 10:47 AMfilterstepTom Adam
06/04/2019, 11:49 AMelizarov
06/04/2019, 2:17 PMilya.gorbunov
06/04/2019, 2:46 PMinfixfiltermapLeoColman
06/04/2019, 3:38 PMilya.gorbunov
06/04/2019, 6:29 PMLeoColman
06/04/2019, 6:31 PM