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Because it's a representation of a higher order fu...
# rx
j
jw
02/24/2019, 4:09 AM
Because it's a representation of a higher order function that lets you pass around observable operators as data
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a
arekolek
02/24/2019, 5:21 PM
I think the question was, in Kotlin you can pass around
transform: Observable<T>.() -> Observable<R>
so there doesn’t seem to be a need for
ObservableTransformer
when writing Kotlin code
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