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kotlinlang

Type inference for function argument with default value.
```
// Inferred as x: String, y: Int = 2, z : String = "hello"
fun foo(x : String, y = 2, z = "hello"){
}
```

It discussed many times. There is no simple way to implement this. If you interested, check Kotlin Forum, you may find explanations from someone from Kotlin Team

could anyone provide a link? i wasn't able to find this, and this would be a verryyy cool feature to have

<https://discuss.kotlinlang.org/t/why-can-not-type-of-function-parameters-with-default-value-be-omited/3641>

They largely dismiss it due to expensiveness, but isn't that all in compilation? Is time to compile _that_ big of a concern?

&gt; Is time to compile _that_ big of a concern?

Most definitely. Have you tried programming in large kotlin/native project before?

nope, but thanks. since i don't have any experience there, I readily accept the opinions of others that have