Mihael
06/13/2019, 12:50 PMSELECT DISTINCT TABLE_NAME
FROM INFORMATION_SCHEMA.COLUMNS
WHERE COLUMN_NAME IN ('SessionId')
AND TABLE_SCHEMA='YourDatabase';
tapac
06/13/2019, 5:19 PMval result = ColumnsTable.
slice(ColumnsTable.tableName).
select {
ColumnsTable,columnName inList listOf("SessionId") and
( ColumnsTable.tableSchema eq "YourDatabase"}.
withDistinct().map { it[ColumnsTable.tableName]
}
Mihael
06/13/2019, 11:13 PM