If I want the outputs and inputs have the same ord...

# coroutines

[Simon Lin]

If I want the outputs and inputs have the same order but with different delays for each item.
Is it efficient below?

fun foo() {
    viewModelScope.launch {
        val inputList = listOf("a", "b", "c")
        val deferredList = mutableListOf<Deferred<String>>()
        repeat(3) { index ->
            deferredList += async {
                delay((1L..10000L).random())
                inputList[index]
            }
        }
        val outputList = deferredList.map { it.await() } // a, b, c
    }
}

[Tijl]

there is awaitAll for your deferredList though in this case it’s mostly a syntactic difference. In a more complex example it will be different (it will fail fast).

[Tijl]

also consider buildList

[Nick Allen]

inputList.map { item -> async { doSuspendStuff(item) } }.awaitAll()