I also don't know the performance implications of that since we're creating an extra channel and flow to wrap the one upstream
z
Zach Klippenstein (he/him) [MOD]
02/10/2020, 4:01 PM
It doesn’t create extra channels, those operators are “fused” and will only create one channel. If you look at the source, these operators (and many more) all create and/or modify a private
ChannelFlow
instance.
k
kevin.cianfarini
02/10/2020, 4:01 PM
oh wow! I didn't know that. You learn something new every day.