val flow3 = flow {
  flow1.collect { emit(it) }
  flow2.collect { emit(it) }
}

is a solution but I'm wondering if there is a simpler solution 😉

So to be clear, every value of

flow1

and

flow2

should only be there once in the resulting flow 😉

Hm, unfortunately still not really what I need because this is sequential. I mean this works in my example code but what if

flow1

for instance needs 5 seconds before producing the first value but

flow2

is faster? Then the first results will still be collected once

flow1

has produced it's values. Also what if any of the flows are not terminal?