it seems i can define 2 methods where the only dif...

# codereview

[christophsturm]

it seems i can define 2 methods where the only difference in signature is the number of parameters that their lambda takes:

fun mf(method: suspend () -> String) {
}
fun mf(method: suspend (String) -> String) {
}

and i can call the method that takes one parameter just fine:

mf({string->"string"})

but how can i call the other method?

mf({"string"}) // fails with overload resolution ambiguity

[Shawn]

I think this is the same question actually https://kotlinlang.slack.com/archives/C0B8MA7FA/p1614590517070000

[Shawn]

where the only difference in signature is the number of parameters that their lambda takes

also I mean, sure, disparate arity means different function types, why wouldn’t that be overloadable?

[christophsturm]

thanks, so the solution is mf({->"string"})

[Matteo Mirk]

You have to look at the lambda type as a whole. So () -> String is a different type than (String) -> String , thus overloading is possible

[christophsturm]

sure. I just was not sure how to indicate which one i want to call at the call site.

[Matteo Mirk]

Yeah that was tricky! I learned it from the linked thread as well