Any way to simplify this by getting rid of

fun String.()

for each lamda inside this map creation?

mapOf<String, String.() -> Unit>(
            "One" to fun String.(){ println(this) }
        )

It gives

Type inference failed. Expected type mismatch: inferred type is Pair<String, () -> Unit> but Pair<String, String.() -> Unit> was expected

if I don't use the

fun String.()

while defining the lambda.

technically speaking you could just explicitly declare the parameter and type in the lambda:

{ str: String -> println(str)

, and that’d pass just fine as a

String.() -> Unit

, but to use

this

I don’t think you can avoid having to use the anonymous

fun

syntax

Thanks @Shawn. Guess I'll just have to pass in the lambda receiver type as an argument for now then.