Any way to simplify this by getting rid of `fun St...

# codereview

[jishindev]

Any way to simplify this by getting rid of fun String.() for each lamda inside this map creation?

mapOf<String, String.() -> Unit>(
            "One" to fun String.(){ println(this) }
        )

It gives Type inference failed. Expected type mismatch: inferred type is Pair<String, () -> Unit> but Pair<String, String.() -> Unit> was expected if I don't use the fun String.() while defining the lambda.

[Shawn]

technically speaking you could just explicitly declare the parameter and type in the lambda: { str: String -> println(str), and that’d pass just fine as a String.() -> Unit, but to use this I don’t think you can avoid having to use the anonymous fun syntax

[Shawn]

at very least you could use expression body syntax:

mapOf(
  "One" to fun String.() = println(this)
)

[jishindev]

Thanks @Shawn. Guess I'll just have to pass in the lambda receiver type as an argument for now then.