Is there a way for me to make

invoke()

inlined or otherwise achieve what I’m attempting in

doWork()

?

Are you sure this is the correct code? Just

invoke()

without parameters would result in

fooImpl()

not

fooImpl { … }

which takes a lambda. What about this:

interface Foo {
  //abstract stuff
}

inline operator fun Foo.invoke(block: () -> Unit) {
  //doing stuff
}

No way to override

invoke

here though and no, you cannot make

inline

functions overridable 🙂

Yes, sorry, mine does take a lambda. That’s a typo from moving my implementation to a most-simple-example state. I’ve been operating under the assumption that it’s impossible to achieve. Thanks for the response!