Is there a way for me to make `invoke()` inlined o...

# codereview

[rook]

Is there a way for me to make invoke() inlined or otherwise achieve what I’m attempting in doWork()?

-.kt

[Marc Knaup]

Are you sure this is the correct code? Just invoke() without parameters would result in fooImpl() not fooImpl { … } which takes a lambda.

What about this:

interface Foo {
  //abstract stuff
}

inline operator fun Foo.invoke(block: () -> Unit) {
  //doing stuff
}

No way to override invoke here though and no, you cannot make inline functions overridable 🙂

[rook]

Yes, sorry, mine does take a lambda. That’s a typo from moving my implementation to a most-simple-example state. I’ve been operating under the assumption that it’s impossible to achieve. Thanks for the response!