you cannot have a lambda that’s generic for all &l...
# functionalp
pakoito
02/21/2019, 6:36 AMyou cannot have a lambda that’s generic for all <T>
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breandan
02/21/2019, 6:41 AMIs this a hard and fast rule? What allows the last example compile?
fun <T> foo(baz: T) = fun (bar: T): T = barp
pakoito
02/21/2019, 6:45 AMthat’ll return a lambda that works for one type
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breandan
02/21/2019, 6:49 AMYes, I see now
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