Does anyone know if `foo { bar(it) }` has a perfor...

# compiler

[raulraja]

Does anyone know if foo { bar(it) } has a performance cost over foo(bar) allocating an extra lambda? If so is this something the Kotlin compiler already optimizes for?

[udalov]

There's no such optimization, foo { bar(it) } will create an extra lambda

[raulraja]

Thanks @udalov for confirming

[dmitry.petrov]

And foo(::bar), if that's what you actually had in mind, will create an extra callable reference.
At the same time, if { bar(it) } has trivial (empty) closure, compiler will generate a single static instance for lambda, and will reuse it.
So, it's a bit more complex.