hello folks given the function: ```fun <T : Any...

# mockk

[Luiz Aguiar]

hello folks
given the function:

fun <T : Any> myFunction(foo: Foo, bar: Bar, response: KClass<T>): MyResponse<T> { do magic }

how can it be mocked to control the returned object?
I tried something like:

every { mockedClass.myFunction(any(), any(), ofType(SomeType::class) } returns SomeType()

but it didn't work... and using the type directly, myFunction(any(), any(), SomeType::class) is never matched.

[ephemient]

why ofType()? that would match a SomeType, not a KClass<SomeType>

[ephemient]

a straightforward

mockedClass.myFunction(any(), any(), SomeType::class)

should work

[ephemient]

if you do want KClass<out SomeType>, you'd have to write a custom matcher, like

myFunction(any(), any(), match<KClass<*>>(SomeType::class::isSuperclassOf))

[Luiz Aguiar]

@ephemient using myFunction(any(), any(), SomeType::class) is never matched… only returns null for it