Is there any way to have a degree adjust for a linearGradient? ```Brush.linearGradient(listOf()))```...

# compose

[Colton Idle]

Is there any way to have a degree adjust for a linearGradient?

Brush.linearGradient(listOf()))

My designer keeps giving me stuff like this 😅

background: linear-gradient(180deg, rgba(5, 64, 87, 0.5) and background: linear-gradient(215.31deg, rgba(255, 255, 255, 0.1)

[ephemient]

180° is just a vertical gradient in reverse, isn't it?

[Colton Idle]

I guess 180 degree was a bad example, but in general, how would I go about setting values like 215 degrees

[ephemient]

looks like Brush.linearGradient doesn't have a way to adjust the angle directly, but you can adjust the start and end offsets to match the angle with some math

[ephemient]

too lazy to work through the trig but luckily somebody else has: https://stackoverflow.com/a/68223861

[Colton Idle]

Oh cool. I didn't know if there was a way to do it out of the box that I was missing. I'll open a FR for this.

[Colton Idle]

if anyone cares to star: https://issuetracker.google.com/issues/204897507

[Chris Sinco [G]]

Thanks for creating that request. I believe we had a similar conversation on this months ago, but I think it wasn’t clear if we should change the API for linearGradient . From what I recall, you can achieve this but through doing some maths (I haven’t done it myself).

[Colton Idle]

Yeah, some of these gradient definitions from my design team are killing me. hahaha

[Colton Idle]

Trying to draw a border with a linear gradient brush that has a degree set is mind blown

[Chris Sinco [G]]

That StackOverflow thread seems promising for creating a utility function in the meantime

[Colton Idle]

Yeah. The stack overflow thread is ace for background, but now creating a border is another story. So far its a lot of copy pasta from the source. 🤞