I have a list of items composed via LazyColumn. If any one of the item gets changed in the list, how...

# compose

[chansek]

I have a list of items composed via LazyColumn. If any one of the item gets changed in the list, how can I make sure only that particular item of LazyColumn gets recomposed instead of the entire LazyColumn.

[Dominaezzz]

By using State<> objects and only calling .value inside the item lambda. Hard to explain without code.

[Albert Chang]

Specify a custom key for each item.

[Dominaezzz]

What code snippet?

[chansek]

Oh sorry @Dominaezzz . I forgot to add the link. https://stackoverflow.com/questions/68328812/compose-lazycolumn-recomposes-all-items-on-single-item-update

[chansek]

@Albert Chang Tried with specifying key, but it still doesn't work.

[Dominaezzz]

Don't think you can avoid re-composition, you're creating new order objects. Real question here I guess is why do you care?

[chansek]

Isn't it going to hit performance? I mean that's the reason, notifyItemInserted(), etc. methods got introduced in RecyclerView, even though notifyDataSetChanged() was already there.