I have a stupid question. If we remember some value and save it to a variable like this `var foo = r...

# compose

[Filip Wiesner]

I have a stupid question.
If we remember some value and save it to a variable like this var foo = remember { "hello" } , when we mutate the variable ( foo = "world" ) it won't save it to next recomposition, right? We just mutate the variable in the current function scope.

[Filip Wiesner]

I am unsure because I know I've done something like this in my early compose experiments and it worked but I know it shouldn't 😅

[Filip Wiesner]

And I am writing article about compose basics and I want to be sure I don't write something stupid.

[wbertan]

I believe so, in your case you have to do foo.value = newValue and to access the value with foo.value.
To use the Delegate you have to use the `by`:

var foo by remember { mutableStateOf("hello") }
        foo = "newValue"

[Filip Wiesner]

I am not using State tho so there is no foo.value and no delegate.

[julioromano]

In “theory” yes.
But IMHO it’s not good practice because composable function calls can be run in any order by the compose runtime.
If you rely on changing foo the way you mentioned, it will be difficult to ensure all composable functions that have foo visible in their scope see the same mutated value of foo.

If you need mutable state you should remember a mutableStateOf("hello").

[Filip Wiesner]

Maybe I didn't explain myself properly. I know I shouldn't do this and I would never do. In my article I am trying to explain the meaning of remember and State separately because I don't want the reader to understand remember { mutableStateOf() } as one thing. While explaining this I realized that I am not 100% sure that I know how it will behave so I just wanted to make sure 😄

it will be difficult to ensure all composable functions that have foo visible in their scope

So if some inner composable function recomposes, will it get the new value of foo variable?

[julioromano]

So if some inner composable function recomposes, will it get the new value of foo variable?

I think the safe answer here is “it’s not possible to know it reliably”, but I feel like I’m reaching the edge of my knowledge here, I’m sure somebody else might give a better answer.

Updated answer: Yes, but only if it recomposes after foo has been mutated.

[Albert Chang]

remember always returns the same instance produced by executing the block in the first composition. foo is just a pointer so changing the value foo points to doesn't affect what remember returns.

So if some inner composable function recomposes, will it get the new value of foo variable?

The inner function captures the pointer so I think the answer is yes.

[Filip Wiesner]

I think that's all I need. Thank you both @julioromano @Albert Chang 👌

[Filip Wiesner]

(I almost wrote "closing this issue" 🤦‍♂️ )

[julioromano]

@Albert Chang Isn’t it possible that the inner function gets re-run directly by compose (i.e. only the inner function is re-run, the outer function is not)? Perhaps because the inner function was reading some other snapshot state object which has changed.

(Sorry if the question sounds weird, I’m deliberately trying to test my mental model of the subject.)

[Albert Chang]

@julioromano As I said what the inner function captures is the pointer which always points to the latest value.

[julioromano]

Got it, so if the code was actually:

var foo = remember { "hello" }
  foo = "newValue"

It means that any other code will see “newValue”, so in this case the remember call is useless, it’s just polluting the composition by adding a “hello” string to it that will never be read.

I get that @Filip Wiesner is asking this for teaching purposes, I just wanted to be sure such a “pattern” would never be actually useful in real life.

[Filip Wiesner]

in this case the remember call is useless, it’s just polluting the composition by adding a “hello” string to it that will never be read

(nitpicking a little bit) It will be read exactly once and assigned to the variable but other than that, that's exactly how I understand it.

[julioromano]

Ah yes, during recompositions the memoized “hello” will be read from the composition and assigned to foo briefly, just to be overwritten by “newValue” right after.

[Filip Wiesner]

For sake of completeness, here is the section of the article I was writing:

[julioromano]

The case I was thinking about earlier is similar to @Filip Wiesner ’s last example but adds another composable (a Button) that recomposes on each click (recomposition is triggered thanks to someState snapshot state object):

@Composable
private fun MyOuterComposable() {
    Column {
        var searchValue = remember { "" }
        var someState by remember { mutableStateOf(".") }
        OutlinedTextField(
            value = searchValue,
            onValueChange = { searchValue = it },
        )
        Button({ someState = someState.plus(".") }) {
            Text("someState: $someState - searchValue: $searchValue")
        }
    }
}

The value of searchValue that Button displays depends on when Button has been recomposed.
If it recomposes after searchValue has been mutated then it will show the mutated value, otherwise not.

Since the order in which composables (i.e. Button in this case) recompose may not always be reliably predicted, we can’t be sure which value of searchValue will be read by Button .

Disclaimer: this kind of code is just for learning purposes, it should never be used in production.

[Filip Wiesner]

Learning about Compose is so exciting! 😄 I can't wait for when I'll use it on a real project.

[Sean McQuillan [G]]

Yes this works as expected (which is not to work due to string immutability), though it's not a recommended practice for the reasons outlined above.

If you put a mutable value in there, you can use it to update stored values without triggering recomposition, which we do using

https://cs.android.com/androidx/platform/frameworks/support/+/androidx-main:compose/[…]kotlin/androidx/compose/ui/node/Ref.kt?q=Ref%3CT%3E%20compose

[Sean McQuillan [G]]

Which I can't find a usage of in remember anywhere anymore

[Sean McQuillan [G]]

TL;DR don't do that unless you're really really sure you know what you're doing and you're building alternative effects like Reducer(...) or Prev(...) 🙂

[julioromano]

What are Reducer(...) or Prev(...) ?
Are they something in compose?
Or you mean Reducer as in Redux ?

[Sean McQuillan [G]]

You can make a composable function that does reducer behavior, which will require access to the previous value; none of this is part of Compose but it's possible to write and you'll need a Ref somewhere in there 🙂