Suppose a code like this: ```class Outer<T> ...

# ksp

[yamasa]

Suppose a code like this:

class Outer<T> {
    inner class Inner
}

val foo: Outer<String>.Inner
    get() = TODO()

Is there a way to get the type argument String from KSPropertyDeclaration.type of the property foo?
I tried fooPropertyDeclaration.type.resolve().declaration.parentDeclaration?.typeParameters?.get(0), but it was T, not String.

[yigit]

you want the type arguments of the KS Type. 1sec

[yigit]

ksType.arguments

[yigit]

https://cs.android.com/androidx/platform/frameworks/support/+/androidx-main:room/com[…]compiler/processing/ksp/KspType.kt;l=64?q=KspType&ss=androidx

[yigit]

in room we needed the declaration as well (KSTypeParameter) to resolve variance when generating java code

[yigit]

so you probably don't need it

[yamasa]

Hmm... Since Inner itself has no type parameter, fooPropertyDeclaration.type.resolve().arguments is empty.
I'd like to access the ksType of Outer, but I don't know how to do it.

[yigit]

oh, hmm

[yigit]

didn't notice that part sorry

[Ting-Yuan Huang]

You don't need to resolve a type reference to get its type arguments.

// returns String
(fooPropertyDeclaration.type.element as KSClassifierReference).qualifier.typeArguments

On the other hand, it looks like a bug to me that the KSType for Inner has no type argument. Unlike nested types, inner types should carry type arguments from their outer types.

[Ting-Yuan Huang]

Filed a bug for this: https://github.com/google/ksp/issues/325

[yamasa]

Thank you. I'm looking forward to it being fixed!