How would I get the class of a KSPropertyDeclarati...

# ksp

[Fabio]

How would I get the class of a KSPropertyDeclaration? I can see it.type.resolve() is a KSType , and I see isAssignableFrom(KSType) but still not sure how to compare it to a KClass like Module::class.java

[yigit]

you need to get the type from the KSClass

[yigit]

you can use asStarProjectedType

[Jiaxiang]

Also KSType.declaration will direct you to the KSClass of that type. However it is recommended to use KSType for comparing to handle subtypee, i.e. use the approach above.

[Fabio]

but how do I get the KSClass from both KSType on one object and KClass on the other object?

[yigit]

what is object ?

[yigit]

oh

[yigit]

you can use Resolver.getClassDeclarationByName("qalified name of Module")
and then get type from it as asStarProjectedType

[yigit]

if you want to find the class of a type, then you can use its declaration but as @Jiaxiang mentioned, it is best to use types for type checking unless you have a case where you don't want to accept subtypes etc

[Fabio]

I made my code work but not sure if this is a code smell:

val moduleKsType =
            org.koin.core.module.Module::class.java
                .let {
                    object : KSName {
                        override fun asString(): String = it.canonicalName
                        override fun getQualifier(): String = "Not important "
                        override fun getShortName(): String = it.simpleName
                    }
                }
                .let {
                    resolver.getClassDeclarationByName(it)
                        ?.asStarProjectedType()
                }

[Fabio]

and then to check for the type of a given val d: KSPropertyDeclaration I'm doing

d.type.resolve().declaration == moduleKsType?.declaration

[Fabio]

(which in a non-ksp project would be equivalent of using the is keyword, as in obj is org.koin.core.module.Module)

[Jiaxiang]

you can simply use resolver.getClassDeclarationByName(name: String) function which will accept a string for name so you don’t have to create that long statement for creating a dummy KSName object.

[Jiaxiang]

Alternatively, if you prefer using reflection, there is also a function fun <reified T> Resolver.getClassDeclarationByName() which will help.

[yigit]

It wouldn't be equal to is check because is check would accept subclasses but i guess you don't have subclasses here

[Fabio]

at this moment I'm not worried with subclasses, probably much later after the POC is ready