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kotlinlang

Ideomatic way to get the closest multiple of .5 to a given float? E.g. `closest(1.03)=1.05`, `closest(1.02)=1.00`, `closest(1.05)=1.05`

The only solution I see out of the box is multiply + round + divide. And it probably also will be the most effective one

So if you wont to round by 0.05 you need something like `round(d*20.0)/20.0`

There are also another two solutions (to get closest to `a` multiple of `b`):
2. `a - a.IEEErem(b)` (`IEEErem` is from `kotlin.math` and iss available only for K/JVM and K/Native)
3. `(a + b/2).let { it - it.mod(b) }`

In both cases we just subtract remainder of division of `a` by `b` to get product of the division's quotient and the divisor `b`.