Ideomatic way to get the closest multiple of .5 to a given float? E.g. `closest(1.03)=1.05`, `closes...

# mathematics

[Sam Stone]

Ideomatic way to get the closest multiple of .5 to a given float? E.g. closest(1.03)=1.05, closest(1.02)=1.00, closest(1.05)=1.05

[altavir]

The only solution I see out of the box is multiply + round + divide. And it probably also will be the most effective one

[altavir]

So if you wont to round by 0.05 you need something like round(d*20.0)/20.0

[Gleb Minaev]

There are also another two solutions (to get closest to a multiple of b):
2. a - a.IEEErem(b) (IEEErem is from kotlin.math and iss available only for K/JVM and K/Native)
3. (a + b/2).let { it - it.mod(b) }

In both cases we just subtract remainder of division of a by b to get product of the division's quotient and the divisor b.

[Sam Stone]

Thank you so much both of you!!