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A function reference passed as an argument to an inline function will _not_ be inlined.  Is that correct?
That's what it looks like from the bytecode, but I'm on shaky ground when making sense of bytecode.

can you provide an example of what you mean?

these are both inlined:
```Unit.let(::println)
Unit.let { println(it) }```

not the contents of println, but there is no wrapper object constructed

e.g. different from `val f: (Any) -&gt; Unit = ::println` / `val f = { println(it) }`

I understand the question to be, "will the contents of `println` be inlined?"

Yup <@UBJF87EBY>.  That's what I intended to ask, but wasn't clear.

Thanks <@UJQB4DJF7>.  `println` will not be inlined.   Just the _call_ to `println` is inlined.

Haha!  Actually, `println` is an inline function itself, so its content _will_ be inlined.  But, if it _wasn't_ an inline function, its content wouldn't be inlined, even when passed as an argument (by function reference) to an inline function.  Phew!  :sweat_smile:

also check up on `noinline`  and `crossinline` : <https://kotlinlang.org/docs/inline-functions.html>