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kotlinlang

When a suspend function calls another, is there an assurance of the order of operations and whether they are synchronous or not?  Will this always print A-B-C regardless of under which conditions x is invoked?
```suspend fun x() {
  print("A")
  y()
  print("C")
}
suspend fun y() {
  print("B")
}```

unless a `suspend fun` escapes <https://elizarov.medium.com/structured-concurrency-722d765aa952|structured concurrency> (either by explicitly giving it a `CoroutineScope` to allow it to do so, or if it breaks conventions by launching into an unrelated scope) then all `suspend fun`s run to completion in sequence

in short: your code will not print A-C-B out of order

this might print A-B-C or A-C-B:
```suspend fun x() {
    coroutineScope {
        print("A")
        y(this@coroutineScope)
        print("B")
    }
}
fun y(scope: CoroutineScope) {
    scope.launch {
        print("C")
    }
}```

|Will this always print A-B-C regardless...
You mean 'A-C-B' in your question right?

but i think we all understood the idea hahah