When a suspend function calls another, is there an assurance of the order of operations and whether ...

# getting-started

[ank]

When a suspend function calls another, is there an assurance of the order of operations and whether they are synchronous or not? Will this always print A-B-C regardless of under which conditions x is invoked?

suspend fun x() {
  print("A")
  y()
  print("C")
}
suspend fun y() {
  print("B")
}

[ephemient]

unless a suspend fun escapes structured concurrency (either by explicitly giving it a CoroutineScope to allow it to do so, or if it breaks conventions by launching into an unrelated scope) then all `suspend fun`s run to completion in sequence

[ephemient]

in short: your code will not print A-C-B out of order

[ephemient]

this might print A-B-C or A-C-B:

suspend fun x() {
    coroutineScope {
        print("A")
        y(this@coroutineScope)
        print("B")
    }
}
fun y(scope: CoroutineScope) {
    scope.launch {
        print("C")
    }
}

[ank]

thank you so much for your answers

[ank]

@ephemient++

[Pablichjenkov]

|Will this always print A-B-C regardless...
You mean 'A-C-B' in your question right?

[ephemient]

oh lol, that affected my responses too

[ank]

yeah sorry meant ACB lol

[ank]

but i think we all understood the idea hahah

[ank]

edited

[Pablichjenkov]

😁