I have a data class called `data class Content( va...

# android

[Arun Sudharsan]

I have a data class called
data class Content( val aName: String, val bName: String)

This is the type how a library is sending the data to the app.
I need to send this to our backend which requires the keys to be like
“a_name” and “b_name” so I tagged the Json(name=“”) annotations on top of them like this,
data class Content( @Json(name="a_name") val aName: String, @Json(name="b_name") val bName: String)

But now the library is shouting with the below error:
com.squareup.moshi.JsonDataException: Required value ‘aName’ (JSON name ‘a_name’) missing at $[1]

My Solution is to create LibraryContent data class and BackendContent data class with the respective names. Is there a better solution? Thanks in advance!

[Chris Lee]

Unclear on the issue. Is it that the same data class ‘Content’ is used for both incoming data, and for delivering data to the back-end (in a slightly different format)?

[Arun Sudharsan]

yes

[Arun Sudharsan]

the name is different.

[Arun Sudharsan]

we cant ask our backend to change the contracts to accept the ones that the library is offering because of naming conventions.

[Chris Lee]

the general pattern for this is as you indicated - separate the objects to match their respective contracts, and then map accordingly.

[Chris Lee]

there’s possibly other shortcuts that are frought with fingerguns, as contracts have a habit of evolving independently.

[Ciaran Sloan]

I would personally not reuse a model across datasources like this. Declaring separate data classes that respect the contract of that datasource is a more scalable solution IMO. ContentLibraryModel ContentApiModel

[Arun Sudharsan]

Thanks for your inputs folks.