I need to get the sorted frequency of distinct elements in a List. This seems to do what I need:

myList.groupingBy { it }.eachCount().toList().sortedBy { it.second }

Is there any shorter and/or more efficient way of doing this? Maybe some shortcut for

groupingBy { it }

?

Not shorter, but avoids creation of a temporary ArrayList:

myList.groupingBy { it }.eachCount().entries.sortedBy { it.value }

(Also, it returns a

List<Map.Entry>

instead of a

List<Pair>

.)