I need to get the sorted frequency of distinct elements in a List. This seems to do what I need: ```...

# stdlib

[Mikael Ståldal]

I need to get the sorted frequency of distinct elements in a List. This seems to do what I need:

myList.groupingBy { it }.eachCount().toList().sortedBy { it.second }

Is there any shorter and/or more efficient way of doing this? Maybe some shortcut for groupingBy { it } ?

[Klitos Kyriacou]

Not shorter, but avoids creation of a temporary ArrayList:

myList.groupingBy { it }.eachCount().entries.sortedBy { it.value }

(Also, it returns a List<Map.Entry> instead of a List<Pair>.)