Is there a good way to declare that a function ret...

# announcements

[Allan Wang]

Is there a good way to declare that a function returns a nonnull type, where the generic used is nullable?

For instance:

interface Call<T> {
    suspend fun call(): T
}

suspend fun <T> Call<T>.callNotNull(): T = call() ?: throw RuntimeException("Example")

val nonnullCall = object : Call<String> {
    override suspend fun call(): String = "notnull"
}

val nullCall = object : Call<String?> {
    override suspend fun call(): String? = null
}

suspend fun t() {
    val r: String = nonnullCall.callNotNull()
    val s: String = nullCall.callNotNull()
}

At its current state, I will get an error for nullCall since s is String?

Type T may or may not be nullable, but the returning type is definitely not null.

I can’t use contracts because this is a suspended function
I can’t make the extension to Call<T?> or it won’t work for nonnullCall

Do I have to make two extension functions for this to work? Is there something like T! that would indicate a type with nullability removed?

[robstoll]

maybe something like fun <T: Any> Call<T?>.callNotNull(): T helps?

[Allan Wang]

That would cause nonnullCall.callNotNull() to fail as the signature is Call<T> instead of Call<T?>

[robstoll]

It was more about an idea not a solution. You could use Call<out T?>.callNotNull()` but that depends on your use case of course