what's an idiomatic way to get a list that has a s...

# announcements

[Joe]

what's an idiomatic way to get a list that has a single element prepended to an existing list. I've been doing: listOf(listOf(newElement), existingList).flatten() but that's a bit cumbersome. realized I can do listOf(newElement).union(existingList), but that gives a Set instead of a List, which isn't always desired.

[nkiesel]

what about listOf(newElement) + existingList

[Joe]

Ha that's probably it! I was looking for a named function and skipped right over +