Hi everyone, Is it possible to get the file name of a class? For example I have Foo.kt containing this class:

class Bar {
  init {
    // Here I want to get the name of the file (Foo)
  }
}

The source file doesn't necessarily exist at runtime. If your class is compiled into a

.class

file which is then packaged into a jar, what file name do you expect to get when you run this program?

I tried this but it gives the path to the main function.

Seems indeed quite hacky to me. Maybe there is something in Kotlin's Metadata on the class that you could use. But I don't know much about this

Here is my use case I have a containing some classes that represents visual forms. That forms contains too many informations like title, labels of the fields, ... etc. Now I want to provide a way to localize these forms in one xml file. So the method will be like this:

fun localize(form: Form) {
  val name = form.fileName()
  // if language is french, look for localization in the file name-fr_FR.xml
  // if language is english, look for localization in the file name-en_GB.xml
}

So basically you want to associate

Form

instances with XML files based on the name of the file containing the form? Why not base this on a convention on class name? Or just specifying the file prefix explicitly in each form (which is more refactoring-proof)?

Yes exactly, I was trying to reduce code and make the program deduct that information. Actually it's based on classname but to make the components in the form reusable it's possible to create a class for a field and insert it in a form. This way I will have to write an xml file foreach field. That's why I wanted to regroup localization of many classes in same xml file. Also you're right about specifying the file prefix explicitly to avoid refactoring problem.